x^2+14x+11=0

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Solution for x^2+14x+11=0 equation:


Simplifying
x2 + 14x + 11 = 0

Reorder the terms:
11 + 14x + x2 = 0

Solving
11 + 14x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-11' to each side of the equation.
11 + 14x + -11 + x2 = 0 + -11

Reorder the terms:
11 + -11 + 14x + x2 = 0 + -11

Combine like terms: 11 + -11 = 0
0 + 14x + x2 = 0 + -11
14x + x2 = 0 + -11

Combine like terms: 0 + -11 = -11
14x + x2 = -11

The x term is 14x.  Take half its coefficient (7).
Square it (49) and add it to both sides.

Add '49' to each side of the equation.
14x + 49 + x2 = -11 + 49

Reorder the terms:
49 + 14x + x2 = -11 + 49

Combine like terms: -11 + 49 = 38
49 + 14x + x2 = 38

Factor a perfect square on the left side:
(x + 7)(x + 7) = 38

Calculate the square root of the right side: 6.164414003

Break this problem into two subproblems by setting 
(x + 7) equal to 6.164414003 and -6.164414003.

Subproblem 1

x + 7 = 6.164414003 Simplifying x + 7 = 6.164414003 Reorder the terms: 7 + x = 6.164414003 Solving 7 + x = 6.164414003 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + x = 6.164414003 + -7 Combine like terms: 7 + -7 = 0 0 + x = 6.164414003 + -7 x = 6.164414003 + -7 Combine like terms: 6.164414003 + -7 = -0.835585997 x = -0.835585997 Simplifying x = -0.835585997

Subproblem 2

x + 7 = -6.164414003 Simplifying x + 7 = -6.164414003 Reorder the terms: 7 + x = -6.164414003 Solving 7 + x = -6.164414003 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + x = -6.164414003 + -7 Combine like terms: 7 + -7 = 0 0 + x = -6.164414003 + -7 x = -6.164414003 + -7 Combine like terms: -6.164414003 + -7 = -13.164414003 x = -13.164414003 Simplifying x = -13.164414003

Solution

The solution to the problem is based on the solutions from the subproblems. x = {-0.835585997, -13.164414003}

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